1
package 回溯法.q22_括号生成.f1;
import java.util.*;
/**
* 暴力法 o(2^2n*n)
*/
public class Solution {
public boolean isValid(String s) {
Stack<Character> stack = new Stack<>();
for (int i = 0; i < s.length(); i++) {
char t = s.charAt(i);
if (t == '(') {
stack.push(t);
} else {
if (stack.empty() || stack.pop() != '(') {
return false;
}
}
}
return stack.empty();
}
public List<String> generateParenthesis(int n) {
List<String> rs = new ArrayList<>();
if (n < 1) {
return rs;
}
String root = "(";
rs.add(root);
for (int k = 0; k < 2 * n - 1; k++) {
List<String> tempList = new ArrayList<>();
for (int i = 0; i < rs.size(); i++) {
String temp = rs.get(i);
tempList.add(temp + "(");
tempList.add(temp + ")");
}
rs.clear();
rs.addAll(tempList);
}
rs.removeIf(s -> !isValid(s));
return rs;
}
public static void main(String[] args) {
new Solution().generateParenthesis(3);
}
}
2
package 回溯法.q22_括号生成.f2;
import java.util.ArrayList;
import java.util.List;
/**
* 回溯法 o((4^n)/(n^1/2))
*/
public class Solution {
public List<String> generateParenthesis(int n) {
List<String> ans = new ArrayList();
backtrack(ans, "", 0, 0, n);
return ans;
}
public void backtrack(List<String> ans, String cur, int open, int close, int max) {
if (cur.length() == max * 2) {
ans.add(cur);
return;
}
if (open < max) {
backtrack(ans, cur + "(", open + 1, close, max);
}
if (close < open) {
backtrack(ans, cur + ")", open, close + 1, max);
}
}
public static void main(String[] args) {
System.out.println(new Solution().generateParenthesis(3));
}
}